Intake temperature science applied to phenolic spacers

[purpelt81]

As I have said multiple times there is only one way to make any pertinent measurememts. I have a b.s. BIS I switched from engineering physics. I was a physics major before that.

[purpelt81]

http://images.tapatalk-cdn.com/15/04/28/a11d43f5ef7bd576e0ca45ec8a5db597.jpg

[purpelt81]

http://en.m.wikipedia.org/wiki/Heat_transfer_coefficient

[purpelt81]

If you have the change in temperatures and an unknown and area also as an unknown your heat flux will equal be equal to your delta t over q which is a unit of area with out knowing one or the other your numbers prove nothing.

[sakimano]

[quote=“JCviggen,post:59,topic:7232”]

Where did I say that, good sir? I definitely said the effect was not zero. Just that has to be very small to the point that 250 bucks is a lot of money for the expected improvements over stock.

And for every example of someone selling phenolic spacers or a race car using them, there are many more which don’t use them. Most cars used in competitions don’t use phenolic spacers. Most manufacturers don’t use them either. Couple weeks ago I saw a relatively modern Ferrari engine in bits, nice big aluminium intake manifold and all. Nothing there to act as a heat barrier. It would cost Ferrari peanuts to include, or even make the manifold out of a different material if heat transfer to the air was an actual concern.

Heck, Aluminium is a poor design choice in general if you believe there is a significant amount of heat being transferred to the air to the point performance degrades. Still most cars both cheap and expensive use them. Some are using plastic (vastly superior heat transfer properties!) on their cheaper models and then fit an Aluminium one to the more expensive ones… shooting themselves in the foot supposedly.

aluminium? your manifold is made of aluminium? that must be a one off

[purpelt81]

Sorry the actual equation would have to be dQ*h= dA/deltaT where dQ is the thermal power given off by the engine, h is the transfer coefficient or how conductive the materials transfering the energy are dA is is the area of direct contact. If you don’t know either dA or delta you cannot have any conclusive results no matter how accurate your heat measurements are which for the record will be not very.